Gas Laws In Action
Use the data you have collected to illustrate the relationship between volume and temperature in Charles's Law.
Enter data from the table in the first blank; then press enter.
Repeat for each blank.
| / | = | / |
| Time (min) |
Temp (k) |
Circumference (cm) |
Diameter (cm) |
Radius (cm) |
Volume (L) |
|---|---|---|---|---|---|
| 0 | 296 | 77.5 | 24.6 | 12.3 | 7.79 |
| 15 | 293 | 77.2 | 24.5 | 12.25 | 7.69 |
| 30 | 287 | 76.7 | 24.4 | 12.2 | 7.60 |
| 45 | 282 | 76.2 | 24.2 | 12.1 | 7.41 |
| 60 | 275 | 75.6 | 24.0 | 12.0 | 7.23 |
That's not correct. Check your numbers and try again.
That's not correct. Use the formula V1/T1 = V2/T2. Try again.
Incorrect. Enter one of the five data points from the Volume column of the chart. Try again.
You have already used the volume {{###}}:Invalid character:Invalid character in the first position of the formula. Enter a volume that you have not used. Try again
That's not correct. Check your numbers and try again.
That's not correct. Use the formula V1/T1 = V2/T2. Try again.
That's not correct. Enter {{###}}. Try again.
Yes. This is a correct illustration of Charles's Law. Click the right arrow to continue.
